or
or
Let, third angle be = x
Second angle = x - 20
First angle = 3( x - 20) = 3x - 60
Sum of angles of triangle = 180
Hence ATQ,
3x - 60 + x - 20 + x = 180
or,5x - 80 = 180
or,5x = 180 + 80 = 260
or,x = 260/5 = 52
∴Second Angle = 52–20 = 32° (ans)
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